Question
Find expected value for the random variable.
its suppost to be a table 6 X 2 i used the .... to represent separation
z.....3......6.....9.....12.......15
p(z)..0.14..0.29..0.36..0.11...0.10
So what i did is i said
e(x) = 3 (0.14)+ 6(0.29)+ etc to all the rest. and my result was 8.22 am i correct that would be the expected value for the reandom variable.
its suppost to be a table 6 X 2 i used the .... to represent separation
z.....3......6.....9.....12.......15
p(z)..0.14..0.29..0.36..0.11...0.10
So what i did is i said
e(x) = 3 (0.14)+ 6(0.29)+ etc to all the rest. and my result was 8.22 am i correct that would be the expected value for the reandom variable.