Which of the following is a point on the graph as described by the function y= (2x+1) to the power of 2-4

Question

(-1,3)
(1,2)
(0,-2)
(-1,-5)

Answer 1

We can plug the x-values into the function and see which ones give us the corresponding y-values.

For (-1,3):
y = (2(-1) + 1)^2 - 4 = (1)^2 - 4 = 1 - 4 = -3 ≠ 3

For (1,2):
y = (2(1) + 1)^2 - 4 = (3)^2 - 4 = 9 - 4 = 5 ≠ 2

For (0,-2):
y = (2(0) + 1)^2 - 4 = (1)^2 - 4 = 1 - 4 = -3 ≠ -2

For (-1,-5):
y = (2(-1) + 1)^2 - 4 = (1)^2 - 4 = 1 - 4 = -3 ≠ -5

None of the given points satisfy the equation of the function, y = (2x + 1)^2 - 4.