The point-slope form of a linear equation is given by: y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.
Given that the point (x1, y1) is (19, -12) and the slope m is -3, we can substitute these values into the point-slope form.
y - (-12) = -3(x - 19)
Simplifying the equation,
y + 12 = -3x + 57
Rearranging the equation to standard form (Ax + By = C),
3x + y = 45
This is the equation of the line passing through the point (19, -12) with a slope of -3.
Use point-slope form to write the equation of a line that passes through the point (19,-12) with slope -3
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