Use point-slope form to write the equation of a line that passes through the point (-11,-13) with slope -2/3

Answer 1

The point-slope form of a linear equation is given by:

y - y1 = m(x - x1)

where (x1, y1) represents a point on the line and m represents the slope.

Using the given information, the equation of the line is:

y - (-13) = (-2/3)(x - (-11))

Simplifying this equation gives:

y + 13 = (-2/3)(x + 11)

Now we can distribute the slope:

y + 13 = (-2/3)x - (2/3)(11)

Simplifying further gives:

y + 13 = (-2/3)x - 22/3

Finally, subtracting 13 from both sides yields the equation of the line in point-slope form:

y = (-2/3)x - 67/3