Use point-slope form to write the equation of a line that passes through the point (-7,14) with slope 2/11

Answer 1

The point-slope form of a linear equation is given by:

y - y1 = m(x - x1)

where (x1, y1) is a point on the line and m is the slope.

In this case, the point is (-7, 14) and the slope is 2/11. Plugging these values into the point-slope form equation, we have:

y - 14 = (2/11)(x - (-7))

Simplifying,

y - 14 = (2/11)(x + 7)

y - 14 = (2/11)x + 14/11

To get the equation into standard form, we can multiply through by 11:

11(y - 14) = 2x + 14

11y - 154 = 2x + 14

Rearranging,

2x - 11y = -168

So, the equation of the line that passes through the point (-7, 14) with slope 2/11 is 2x - 11y = -168.