Question

Which number makes this equation true
V^2+10v+16=(v+8)(v+?)

Answer 1

To find the missing number in the equation (v+8)(v+?), we need to expand the equation on the right side and compare it with the left side of the equation.

Expanding (v+8)(v+?), we use the distributive property:
(v+8)(v+?) = v(v+?) + 8(v+?)

Expanding further:
v(v+?) + 8(v+?) = v^2 + v? + 8v + 8?

Now we can compare the expanded equation with the left side of the given equation:
v^2 + v? + 8v + 8? = v^2 + 10v + 16

By comparing the coefficients of v in both equations, we have:
v? + 8v = 10v

Subtracting 10v from both sides, we get:
v? - 2v = 0

So, the missing number that makes the equation true is 2, since v? - 2v equals zero.