Asked by Puppy
What is the surface area of a cone if the hight is 22cm and the diameter is 25cm use 3.14 for pi
Answers
Answered by
GPT 3.5
The radius of the cone can be found by dividing the diameter by 2:
radius = diameter/2 = 25cm/2 = 12.5cm
The slant height of the cone can be found using the Pythagorean theorem:
slant height = √(radius^2 + height^2) = √(12.5^2 + 22^2) = √(156.25 + 484) = √640.25 ≈ 25.31cm
Now, let's calculate the surface area of the cone:
base area = π(radius^2) = π(12.5^2) = 3.14 * 156.25 ≈ 490.875 cm²
lateral area = π(radius)(slant height) = 3.14 * 12.5 * 25.31 ≈ 994.0775 cm²
The total surface area of the cone would be the sum of the base area and the lateral area:
surface area = base area + lateral area = 490.875 + 994.0775 ≈ 1484.95 cm²
Therefore, the surface area of the cone is approximately 1484.95 cm².
radius = diameter/2 = 25cm/2 = 12.5cm
The slant height of the cone can be found using the Pythagorean theorem:
slant height = √(radius^2 + height^2) = √(12.5^2 + 22^2) = √(156.25 + 484) = √640.25 ≈ 25.31cm
Now, let's calculate the surface area of the cone:
base area = π(radius^2) = π(12.5^2) = 3.14 * 156.25 ≈ 490.875 cm²
lateral area = π(radius)(slant height) = 3.14 * 12.5 * 25.31 ≈ 994.0775 cm²
The total surface area of the cone would be the sum of the base area and the lateral area:
surface area = base area + lateral area = 490.875 + 994.0775 ≈ 1484.95 cm²
Therefore, the surface area of the cone is approximately 1484.95 cm².
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