What is the surface area of a cone if the hight is 22cm and the diameter is 25cm use 3.14 for pi

Answer 1

The radius of the cone can be found by dividing the diameter by 2:

radius = diameter/2 = 25cm/2 = 12.5cm

The slant height of the cone can be found using the Pythagorean theorem:

slant height = √(radius^2 + height^2) = √(12.5^2 + 22^2) = √(156.25 + 484) = √640.25 ≈ 25.31cm

Now, let's calculate the surface area of the cone:

base area = π(radius^2) = π(12.5^2) = 3.14 * 156.25 ≈ 490.875 cm²

lateral area = π(radius)(slant height) = 3.14 * 12.5 * 25.31 ≈ 994.0775 cm²

The total surface area of the cone would be the sum of the base area and the lateral area:

surface area = base area + lateral area = 490.875 + 994.0775 ≈ 1484.95 cm²

Therefore, the surface area of the cone is approximately 1484.95 cm².