Find the value of the function y=3x2−21 when x=4 .(1 point)

Answer 1

To find the value of the function y=3x^2−21 when x=4, substitute x=4 into the function and evaluate.

So, y = 3(4^2) - 21
= 3(16) - 21
= 48 - 21
= 27

Therefore, when x=4, the value of the function y=3x^2−21 is 27.