Question

Suppose a spider was able to create one thread that would extend from the top-right back corner of its tank to the bottom-left front corner. Approximately how long would that thread need to be for the tank below? The path of the spider's thread is shown with a red dotted line. Round your answer to the nearest tenth of an inch.

The diagonal of the bottom of the tank is
inches. To the nearest tenth of an inch, the length of the spider's thread is
inches.

35in , 16in, 12in

Answer 1

is this right

Answer 2

To find the length of the spider's thread, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, the length of the hypotenuse (the spider's thread) is unknown, one side of the triangle is 35 inches, and the other side is 16 inches. We can label the length of the hypotenuse as x.

Using the Pythagorean theorem, we have:

x^2 = 35^2 + 16^2
x^2 = 1225 + 256
x^2 = 1481

Now we can solve for x by taking the square root of both sides:

x = sqrt(1481)
x ≈ 38.5 inches

Therefore, the length of the spider's thread to the nearest tenth of an inch is approximately 38.5 inches.

Answer 3

I apologize for the mistake. Let's re-calculate it correctly.

The diagonal of the bottom of the tank forms a right triangle with the two other sides measuring 12 inches and 16 inches. Using the Pythagorean theorem, we can find the length of the diagonal.

Let's denote the length of the diagonal as x.

Using the Pythagorean theorem:

x^2 = 12^2 + 16^2
x^2 = 144 + 256
x^2 = 400

Taking the square root of both sides:

x = sqrt(400)
x = 20 inches

Therefore, the length of the spider's thread to the nearest tenth of an inch is approximately 20 inches.