Question
Given the sum 99=33+66, rewrite 33+66 using their GCF and multiplication.
____ ( 1 + 2 )
____ ( 1 + 2 )
Answers
Answer
ty
Answer
Given the sum 30=12+18 , rewrite 12+18 using their GCF and multiplication.(1 point)
6 ( )
6 ( )
Answer
Given the sum 85, rewrite 35+50 using their GCF and multiplication.(1 point)
___ ( 7 + 10 )
___ ( 7 + 10 )
Answer
Given the sum 100=25+75 , rewrite 25+75 using their GCF and multiplication.(1 point)
25 ( )
25 ( )
Answer
Philip is sorting acorns he collected. He has 92 acorns: 66 still have their tops, 26 do not. Philip wants to sort the acorns into groups with the same number of acorns, including some with and without tops. He wants each group to have an equal number of acorns with tops and an equal number of acorns without tops. Which answer best shows how Philip can represent how he should sort the acorns?(1 point) Responses 1(66+26) 1 left parenthesis 66 plus 26 right parenthesis 2(33+13) 2 left parenthesis 33 plus 13 right parenthesis 6(11+4) 6 left parenthesis 11 plus 4 right parenthesis 24(3+1)
Answer
Mei is playing a game with numbers. She decides to rewrite the number 78 using the Distributive Property. Which answer is a correct way to rewrite 78 using the Distributive Property of Multiplication over Addition?(1 point) Responses 78=18+60=(6×3)+(6×10)=6(3+10) 78 equals 18 plus 60 equals left parenthesis 6 times 3 right parenthesis plus left parenthesis 6 times 10 right parenthesis equals 6 left parenthesis 3 plus 10 right parenthesis 78=22+56=(2×11)+(2×28)=2(11×28) 78 equals 22 plus 56 equals left parenthesis 2 times 11 right parenthesis plus left parenthesis 2 times 28 right parenthesis equals 2 left parenthesis 11 times 28 right parenthesis 78=24+54=(6×4)+(6×9)=6(4×9) 78 equals 24 plus 54 equals left parenthesis 6 times 4 right parenthesis plus left parenthesis 6 times 9 right parenthesis equals 6 left parenthesis 4 times 9 right parenthesis 78=11+67=(1×11)+(1×67)=1(11×67)
Answer
Sven is making a school supply display. Sven has 52 notebooks and 42 binders. Sven wants to group the supplies in the display so that there are an equal number of supplies in each group. If we know that Sven puts the same number of notebooks and the same number of binders into each group, how many groups did he display and how many of each item went into each group? Represent your answer using the Distributive Property of Multiplication over Addition.(1 point) Responses Sven made 1 group. He put all 52 notebooks and all 42 binders into that one group. Using the Distributive Property, the answer can be shown as 1(52+42). Sven made 1 group. He put all 52 notebooks and all 42 binders into that one group. Using the Distributive Property, the answer can be shown as 1 left parenthesis 52 plus 42 right parenthesis . Sven made 1 group. He put all 52 notebooks and all 42 binders into that one group. Using the Distributive Property, the answer can be shown as 1(52×42). Sven made 1 group. He put all 52 notebooks and all 42 binders into that one group. Using the Distributive Property, the answer can be shown as 1 left parenthesis 52 times 42 right parenthesis . Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2(26×21). Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2 left parenthesis 26 times 21 right parenthesis . Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2(26+21). Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2 left parenthesis 26 plus 21 right parenthesis .
Answer
Given the sum 100=64+36, rewrite 64+36 using their GCF and multiplication.(1 point) Responses 4(16+9) 4 left parenthesis 16 plus 9 right parenthesis 4(16×9) 4 left parenthesis 16 times 19 right parenthesis 1(64+36) 1 left parenthesis 64 plus 36 right parenthesis 2(32+18)
Answer
Given the sum 18=6+12, rewrite 6+12 using their GCF and multiplication. (1 point) Responses 1(6+12) 1 times open paren 6 plus 12 close paren 6(1×2) 6 times open paren 1 times 2 close paren 3(2+4) 3 times open paren 2 plus 4 close paren 6(1+2)
Answer
thx sm for your help byeeeeeeeeeee
Answered by
GPT 3.5
The GCF of 33 and 66 is 33.
33 + 66 can be rewritten as:
33 * (1 + 2)
33 + 66 can be rewritten as:
33 * (1 + 2)
Answered by
GPT 3.5
You're welcome! If you have any more questions, feel free to ask.
Answered by
GPT 3.5
The GCF of 12 and 18 is 6.
12 + 18 can be rewritten as:
6 * (2 + 3)
12 + 18 can be rewritten as:
6 * (2 + 3)
Answered by
GPT 3.5
The GCF of 35 and 50 is 5.
35 + 50 can be rewritten as:
5 * (7 + 10)
35 + 50 can be rewritten as:
5 * (7 + 10)
Answered by
GPT 3.5
The GCF of 25 and 75 is 25.
25 + 75 can be rewritten as:
25 * (1 + 3)
25 + 75 can be rewritten as:
25 * (1 + 3)
Answered by
GPT 3.5
To sort the acorns into groups with the same number of acorns with tops and without tops, the total number of acorns must be divisible by the number of groups.
In this case, the number of acorns with tops is 66 and the number without tops is 26. The greatest common factor (GCF) of 66 and 26 is 2.
To divide the acorns into groups with an equal number of acorns with and without tops, we divide both numbers by the GCF:
66 divided by 2 is 33.
26 divided by 2 is 13.
Therefore, Philip can sort the acorns into groups of 33 acorns with tops and 13 acorns without tops.
The correct answer is: 2(33+13)
In this case, the number of acorns with tops is 66 and the number without tops is 26. The greatest common factor (GCF) of 66 and 26 is 2.
To divide the acorns into groups with an equal number of acorns with and without tops, we divide both numbers by the GCF:
66 divided by 2 is 33.
26 divided by 2 is 13.
Therefore, Philip can sort the acorns into groups of 33 acorns with tops and 13 acorns without tops.
The correct answer is: 2(33+13)
Answered by
GPT 3.5
To rewrite the number 78 using the Distributive Property of Multiplication over Addition, we need to break it down into two numbers that can be factored out.
We can rewrite 78 as:
78 = 6 * 13
Therefore, the correct answer is: 78 = 6(13)
We can rewrite 78 as:
78 = 6 * 13
Therefore, the correct answer is: 78 = 6(13)
Answered by
GPT 3.5
To find the number of groups and the number of each item in each group, we need to find the greatest common factor (GCF) of 52 and 42.
The GCF of 52 and 42 is 2.
To divide the supplies into groups with an equal number of notebooks and binders, we divide both numbers by the GCF:
52 divided by 2 is 26.
42 divided by 2 is 21.
Therefore, Sven made 2 groups, with 26 notebooks and 21 binders in each group.
Using the Distributive Property of Multiplication over Addition, the answer can be shown as: 2(26 + 21)
The GCF of 52 and 42 is 2.
To divide the supplies into groups with an equal number of notebooks and binders, we divide both numbers by the GCF:
52 divided by 2 is 26.
42 divided by 2 is 21.
Therefore, Sven made 2 groups, with 26 notebooks and 21 binders in each group.
Using the Distributive Property of Multiplication over Addition, the answer can be shown as: 2(26 + 21)
Answered by
GPT 3.5
The GCF of 64 and 36 is 4.
64 + 36 can be rewritten as:
4 * (16 + 9)
Therefore, the correct answer is: 4(16 + 9)
64 + 36 can be rewritten as:
4 * (16 + 9)
Therefore, the correct answer is: 4(16 + 9)
Answered by
GPT 3.5
The GCF of 6 and 12 is 6.
6 + 12 can be rewritten as:
6 * (1 + 2)
Therefore, the correct answer is: 6(1 + 2)
6 + 12 can be rewritten as:
6 * (1 + 2)
Therefore, the correct answer is: 6(1 + 2)
Answered by
GPT 3.5
You're welcome! I'm glad I could help. If you have any more questions in the future, feel free to ask. Goodbye and take care!
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