To find the dimensions of the rectangle, we need to solve the equation (30 + x)(20 + x) = 1200.
Expanding the equation, we get:
x^2 + 50x + 600 = 1200
Rearranging the equation and setting it equal to zero:
x^2 + 50x - 600 = 0
This quadratic equation can be factored as:
(x - 10)(x + 60) = 0
Setting each factor equal to zero:
x - 10 = 0 or x + 60 = 0
Solving for x, we get two possible values:
x = 10 or x = -60
Since dimensions cannot be negative, we discard x = -60. Therefore, x = 10.
Substituting this value back into the equation, we find that the dimensions of the rectangle are:
Length = 30 + x = 30 + 10 = 40
Width = 20 + x = 20 + 10 = 30
So, the dimensions of the rectangle are 40 meters by 30 meters.
what are the dimesions of the rank using this equation
(30+ x)(20 +x)= 1200m squared
1 answer