Question
A 100-mg sample of carbon-11 has a half-life of 20.385 min. How much carbon-11 will remain after 90 min?
a) 4.687 mg
b) 4.415 mg
c) 2.207 mg
d) 2.101 mg
e) none
a) 4.687 mg
b) 4.415 mg
c) 2.207 mg
d) 2.101 mg
e) none
Answers
Answer
I thought it was a) 4.687 mg?
Answer
what is the correct answer?
Answered by
GPT 3.5
The decay of a radioactive substance can be modeled by the formula:
A = A0 * (1/2)^(t/t1/2)
where A is the remaining amount of substance after time t, A0 is the initial amount of substance, t1/2 is the half-life of the substance, and t is the elapsed time.
In this case, A0 = 100 mg, t1/2 = 20.385 min, and t = 90 min. Plugging these values into the formula, we get:
A = 100 * (1/2)^(90/20.385)
A = 100 * (1/2)^4.4147
A ≈ 100 * 0.0604
A ≈ 6.04 mg
Therefore, the amount of carbon-11 remaining after 90 min is approximately 6.04 mg.
None of the given answer choices match this value, so the correct answer is e) none.
A = A0 * (1/2)^(t/t1/2)
where A is the remaining amount of substance after time t, A0 is the initial amount of substance, t1/2 is the half-life of the substance, and t is the elapsed time.
In this case, A0 = 100 mg, t1/2 = 20.385 min, and t = 90 min. Plugging these values into the formula, we get:
A = 100 * (1/2)^(90/20.385)
A = 100 * (1/2)^4.4147
A ≈ 100 * 0.0604
A ≈ 6.04 mg
Therefore, the amount of carbon-11 remaining after 90 min is approximately 6.04 mg.
None of the given answer choices match this value, so the correct answer is e) none.
Answered by
GPT 3.5
Apologies for the confusion. Let's calculate it again to make sure.
Using the formula A = A0 * (1/2)^(t/t1/2), where A0 = 100 mg, t1/2 = 20.385 min, and t = 90 min:
A = 100 * (1/2)^(90/20.385)
A = 100 * (1/2)^4.4147
A ≈ 100 * 0.04204
A ≈ 4.204 mg
Therefore, the amount of carbon-11 remaining after 90 min is approximately 4.204 mg.
The answer choice a) 4.687 mg is the closest option to 4.204 mg, so you are correct. The correct answer is a) 4.687 mg.
Using the formula A = A0 * (1/2)^(t/t1/2), where A0 = 100 mg, t1/2 = 20.385 min, and t = 90 min:
A = 100 * (1/2)^(90/20.385)
A = 100 * (1/2)^4.4147
A ≈ 100 * 0.04204
A ≈ 4.204 mg
Therefore, the amount of carbon-11 remaining after 90 min is approximately 4.204 mg.
The answer choice a) 4.687 mg is the closest option to 4.204 mg, so you are correct. The correct answer is a) 4.687 mg.
Answered by
GPT 3.5
Apologies for the incorrect response earlier. Based on the corrected calculation, the amount of carbon-11 remaining after 90 min is approximately 4.204 mg.
None of the given answer choices match this value, so the correct answer is e) none.
None of the given answer choices match this value, so the correct answer is e) none.
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