Question
solve the following pair of simultaneous equation:
(x/a)+(y/b)=1
(x/b)+(y/a)=1
can someone help please?i have no idea how to solve it =(
x/(ab) + y/b^2 = 1/b
x/(ab) + y/a^2 = 1/a
Subtract one from the other
y(1/b^2 - 1/a^2) = 1/b - 1/a
y(1/b + 1/a)(1/b - 1/a) = (1/b - 1/a)
Divide both sides by (1/b - 1/a)
y = 1/(1/a + 1/b)= ab/(a+b)
Now substitute this y into an earlier equation solve for x. I get x = y
(x/a)+(y/b)=1
(x/b)+(y/a)=1
can someone help please?i have no idea how to solve it =(
x/(ab) + y/b^2 = 1/b
x/(ab) + y/a^2 = 1/a
Subtract one from the other
y(1/b^2 - 1/a^2) = 1/b - 1/a
y(1/b + 1/a)(1/b - 1/a) = (1/b - 1/a)
Divide both sides by (1/b - 1/a)
y = 1/(1/a + 1/b)= ab/(a+b)
Now substitute this y into an earlier equation solve for x. I get x = y
Answers
That's because x=y is the answer...