To find the coordinates of point J, we need to determine the midpoint of segment AB.
Segment AB has an x-coordinate of -2 at point A and an x-coordinate of 2 at point B. To find the midpoint, we take the average of the x-coordinates: (-2 + 2)/2 = 0.
Similarly, segment AB has a y-coordinate of -1 at point A and a y-coordinate of 7 at point B. To find the midpoint, we take the average of the y-coordinates: (-1 + 7)/2 = 3.
Therefore, the coordinates of point J are (0, 3).
Segment upper A upper B is graphed on a coordinate plane. The x-axis ranges from negative 2 to 2 in increments of 1. The y-axis ranges from negative 1 to 7 in increments of 1.
Determine the coordinates of point J on AB¯¯¯¯¯¯¯¯ so that the ratio of AJ
to JB
is 1:1.
1 answer