Asked by Rachale
Let f(x) = 6/x-1 and g(x) = 1+3/x. Please find the composite function of (fog)(x)
Answers
Answered by
MathMate
(fog)(x) is a notation for substituting g(x) for x in the definition of f(x), in other words,
(fog)(x) = f(g(x))
Using f(x) = 6/x-1
and g(x) = 1+3/x
you would find
(fog)(x)
= f(g(x))
= 6/g(x) -1
= 6/(1+3/x) - 1
= (5x-3)/(x+3)
(fog)(x) = f(g(x))
Using f(x) = 6/x-1
and g(x) = 1+3/x
you would find
(fog)(x)
= f(g(x))
= 6/g(x) -1
= 6/(1+3/x) - 1
= (5x-3)/(x+3)
Answered by
Rachale
So in other words the final answer would be what? I got 2x. Is this correct?
Answered by
MathMate
I got (5x-3)/(x+3).
Can you show me how you got 2x?
Can you show me how you got 2x?
Answered by
MathMate
Actually, it slipped my memory:
There is probably a mis-interpretation of the parentheses:
f(x) = 6/<b>(x-1)</b> and g(x) = 1+3/x
so
f ยบ g (x)
=f(g(x))
=f(+3/x)
=6/(1+3/x-1)
=6/(3/x)
=2x
If this is the case, the answer is (A).
See:
http://www.jiskha.com/display.cgi?id=1245900271
There is probably a mis-interpretation of the parentheses:
f(x) = 6/<b>(x-1)</b> and g(x) = 1+3/x
so
f ยบ g (x)
=f(g(x))
=f(+3/x)
=6/(1+3/x-1)
=6/(3/x)
=2x
If this is the case, the answer is (A).
See:
http://www.jiskha.com/display.cgi?id=1245900271
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