Question

Solve the system of equations below.
3x + 4y = 10
6x - 2y = 40
A. (-2,-6)
B. (2,-6)
C. (6, -2)
D. (2, 6)

Answer 1

To solve this system of equations, we can use the method of substitution.

First, let's solve the first equation for x:
3x + 4y = 10
3x = 10 - 4y
x = (10 - 4y)/3

Now, substitute this expression for x in the second equation:
6x - 2y = 40
6((10 - 4y)/3) - 2y = 40
(20 - 8y) - 2y = 40
20 - 8y - 2y = 40
20 - 10y = 40
-10y = 20
y = -2

Now, substitute this value of y back into the first equation to find x:
3x + 4y = 10
3x + 4(-2) = 10
3x - 8 = 10
3x = 18
x = 6

So, the solution to the system of equations is x = 6 and y = -2.

Therefore, the answer is C. (6, -2)