Question

Let f(x) = 6/x-1 and g(x) = 1+3/x. Please fing the composite function.

This is what i got so far.

=f (1+3/x)

=6/x-1

= =f (1+3/x)
= 6/ [1+3/x - 1]

How do I get the composite?

Answer 1

The definition of a composite function:
f º g (x) means f (g(x) ), which tells you to work out g(x) first, and then fill that answer into f. See
(Broken Link Removed)

In this case,
f(x) = 6/x-1 and g(x) = 1+3/x
so
f º g (x)
=f(g(x))
=f(<b>1+3/x</b>)
=6/(<b>1+3/x</b>)-1
=6x/(x+3)-1
=(6x-(x+3))/(x+3)
=(5x-3)/(x+3)

Answer 2

and the composite function would be?

A.(fog)(x)= (2x)
B.(fog)(x) =2/x
C.(fog)(x)=(6/x-1)(1+3/x
D.(fog)(x)=1+18/x(x-1)

Answer 3

There is probably a mis-interpretation of the parentheses:
f(x) = 6/<b>(x-1)</b> and g(x) = 1+3/x
so
f º g (x)
=f(g(x))
=f(<i>+3/x</i>)
=6/(<b><i>1+3/x</i>-1</b>)
=6/(3/x)
=2x
If this is the case, the answer is (A).

Answer 4

This is what I thought as well. Thanks!