According to the Fundamental Theorem of Algebra, 4x^2+11x−20=0 has two solutions. How many of those solutions are integers?(1 point)

Answer 1

To determine if the two solutions are integers, we need to find the solutions to the equation 4x^2+11x−20=0.

Using factoring or the quadratic formula, we can find the solutions:

4x^2+11x−20=0
(4x-5)(x+4)=0

Setting each factor equal to zero gives us:

4x-5=0 or x+4=0

Solving for x gives us:

x = 5/4 or x = -4

Only one of the solutions, x = -4, is an integer. Therefore, there is one integer solution. Answer: \boxed{1}.