Question

Please Solve:

a. 6x^2 = 36

b. 2x^2-20= 0

c. 4x^2+12=0

Answer 1

a.
6x² = 36
x² = 36/6
x² = 6
x = sqrt(6)

b. and c. can be solved similarly.
Post if you could use additional help or would like to check answers.

Answer 2

Could it be root - 6 as well cause
-6*-6 = 36?

Answer 3

±sqrt(6) would be correct, approximately equal to ±2.449489742783178...
( 2.449...)² = 6
(-2.449...)² = 6

But sqrt(-6) would equal to sqrt(6)*i, a complex number.
( ±2.449...*i) ²
= (±2.449...)² * i ²
= 6*(-1)
=-6

Answer 4

So am i correct? Can i use both root 6 and -root 6

Answer 5

The two roots are indeed root 6 and -root 6, but not root(-6).

Answer 6

Got it thanks!