Question
Use the image to answer the question.
A graph shows quadrant 1 with the x-axis and y-axis ranging from 0 to positive 5. Data points marked are point A at left parenthesis 1 comma 2 right parenthesis, point B at left parenthesis 3 comma 2 right parenthesis, point C at left parenthesis 3 comma 4 right parenthesis, and point D at left parenthesis 1 comma 4 right parenthesis. A line joins points A to B, B to C, C to D, and D to A, forming a rectangle.
Apply the Pythagorean Theorem to find the length of the diagonal of the square. Round your answer to the nearest hundredth, if necessary.
(1 point)
Responses
2.83
2.83
4
4
8
8
4.24
A graph shows quadrant 1 with the x-axis and y-axis ranging from 0 to positive 5. Data points marked are point A at left parenthesis 1 comma 2 right parenthesis, point B at left parenthesis 3 comma 2 right parenthesis, point C at left parenthesis 3 comma 4 right parenthesis, and point D at left parenthesis 1 comma 4 right parenthesis. A line joins points A to B, B to C, C to D, and D to A, forming a rectangle.
Apply the Pythagorean Theorem to find the length of the diagonal of the square. Round your answer to the nearest hundredth, if necessary.
(1 point)
Responses
2.83
2.83
4
4
8
8
4.24
Answers
Answer
Apply the Pythagorean Theorem to find the length between (2, 5) and (7, 3) . Round your answer to the nearest hundredth, if necessary.(1 point)
Responses
4.58
4.58
2.65
2.65
29
29
5.39
Responses
4.58
4.58
2.65
2.65
29
29
5.39
Answer
Apply the Pythagorean Theorem to find the length between (−1, 6) and (5, −2) . Round your answer to the nearest hundredth, if necessary.(1 point)
Responses
14
14
9.22
9.22
100
100
10
Responses
14
14
9.22
9.22
100
100
10
Answer
Use the image to answer the question.
A graph shows four quadrants with the x-axis and y-axis both ranging from negative 5 to positive 5 in increments of 1. Unlabeled data points marked are at left parenthesis negative 2 comma negative 1 right parenthesis, and at left parenthesis 2 comma 4 right parenthesis. A straight line joins the two lines with a positive slope.
Apply the Pythagorean Theorem to find the length between the two points. Round your answer to the nearest hundredth, if necessary.
(1 point)
Responses
5.57
5.57
41
41
9
9
6:40
A graph shows four quadrants with the x-axis and y-axis both ranging from negative 5 to positive 5 in increments of 1. Unlabeled data points marked are at left parenthesis negative 2 comma negative 1 right parenthesis, and at left parenthesis 2 comma 4 right parenthesis. A straight line joins the two lines with a positive slope.
Apply the Pythagorean Theorem to find the length between the two points. Round your answer to the nearest hundredth, if necessary.
(1 point)
Responses
5.57
5.57
41
41
9
9
6:40
Answer
Use the image to answer the question.
A graph shows four quadrants with the x-axis and y-axis both ranging from negative 5 to positive 5 in increments of 1. Data points marked are point A at left parenthesis 2 comma negative 3 right parenthesis, and point B at left parenthesis 5 comma 5 right parenthesis.
Apply the Pythagorean Theorem to find the length between the two points. Round your answer to the nearest hundredth, if necessary.
(1 point)
Responses
11
11
8.54
8.54
73
73
7.62
A graph shows four quadrants with the x-axis and y-axis both ranging from negative 5 to positive 5 in increments of 1. Data points marked are point A at left parenthesis 2 comma negative 3 right parenthesis, and point B at left parenthesis 5 comma 5 right parenthesis.
Apply the Pythagorean Theorem to find the length between the two points. Round your answer to the nearest hundredth, if necessary.
(1 point)
Responses
11
11
8.54
8.54
73
73
7.62
Answered by
GPT 3.5
To find the length of the diagonal of the square, we need to find the distance between points A and C (or points B and D) using the Pythagorean Theorem.
The distance between A and C can be found using the formula:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of points A and C, we have:
d = sqrt((3 - 1)^2 + (4 - 2)^2)
Simplifying:
d = sqrt(2^2 + 2^2)
d = sqrt(4 + 4)
d = sqrt(8)
Rounding to the nearest hundredth, the length of the diagonal of the square is approximately 2.83.
The distance between A and C can be found using the formula:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of points A and C, we have:
d = sqrt((3 - 1)^2 + (4 - 2)^2)
Simplifying:
d = sqrt(2^2 + 2^2)
d = sqrt(4 + 4)
d = sqrt(8)
Rounding to the nearest hundredth, the length of the diagonal of the square is approximately 2.83.
Answered by
GPT 3.5
To find the length between (2, 5) and (7, 3) using the Pythagorean Theorem, we can use the formula:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of the two points, we have:
d = sqrt((7 - 2)^2 + (3 - 5)^2)
Simplifying:
d = sqrt(5^2 + (-2)^2)
d = sqrt(25 + 4)
d = sqrt(29)
Rounding to the nearest hundredth, the length between (2, 5) and (7, 3) is approximately 5.39.
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of the two points, we have:
d = sqrt((7 - 2)^2 + (3 - 5)^2)
Simplifying:
d = sqrt(5^2 + (-2)^2)
d = sqrt(25 + 4)
d = sqrt(29)
Rounding to the nearest hundredth, the length between (2, 5) and (7, 3) is approximately 5.39.
Answered by
GPT 3.5
To find the length between (-1, 6) and (5, -2) using the Pythagorean Theorem, we can use the formula:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of the two points, we have:
d = sqrt((5 - (-1))^2 + (-2 - 6)^2)
Simplifying:
d = sqrt((5 + 1)^2 + (-2 - 6)^2)
d = sqrt(6^2 + (-8)^2)
d = sqrt(36 + 64)
d = sqrt(100)
Rounding to the nearest hundredth, the length between (-1, 6) and (5, -2) is 10.
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of the two points, we have:
d = sqrt((5 - (-1))^2 + (-2 - 6)^2)
Simplifying:
d = sqrt((5 + 1)^2 + (-2 - 6)^2)
d = sqrt(6^2 + (-8)^2)
d = sqrt(36 + 64)
d = sqrt(100)
Rounding to the nearest hundredth, the length between (-1, 6) and (5, -2) is 10.
Answered by
GPT 3.5
To find the length between the points (-2, -1) and (2, 4) using the Pythagorean Theorem, we can use the formula:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of the two points, we have:
d = sqrt((2 - (-2))^2 + (4 - (-1))^2)
Simplifying:
d = sqrt((2 + 2)^2 + (4 + 1)^2)
d = sqrt(4^2 + 5^2)
d = sqrt(16 + 25)
d = sqrt(41)
Rounding to the nearest hundredth, the length between the points (-2, -1) and (2, 4) is approximately 6.40.
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of the two points, we have:
d = sqrt((2 - (-2))^2 + (4 - (-1))^2)
Simplifying:
d = sqrt((2 + 2)^2 + (4 + 1)^2)
d = sqrt(4^2 + 5^2)
d = sqrt(16 + 25)
d = sqrt(41)
Rounding to the nearest hundredth, the length between the points (-2, -1) and (2, 4) is approximately 6.40.
Answered by
GPT 3.5
To find the length between the points (2, -3) and (5, 5) using the Pythagorean Theorem, we can use the formula:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of the two points, we have:
d = sqrt((5 - 2)^2 + (5 - (-3))^2)
Simplifying:
d = sqrt((3)^2 + (8)^2)
d = sqrt(9 + 64)
d = sqrt(73)
Rounding to the nearest hundredth, the length between the points (2, -3) and (5, 5) is approximately 8.54.
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of the two points, we have:
d = sqrt((5 - 2)^2 + (5 - (-3))^2)
Simplifying:
d = sqrt((3)^2 + (8)^2)
d = sqrt(9 + 64)
d = sqrt(73)
Rounding to the nearest hundredth, the length between the points (2, -3) and (5, 5) is approximately 8.54.
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