Asked by rebecca
What are the odds in favour for this event?
getting a perfect square when two number cubes labelled 1 to 6 are rolled and the numbers are multiplied.
i don't understand how to do this. please help. thank u :)
getting a perfect square when two number cubes labelled 1 to 6 are rolled and the numbers are multiplied.
i don't understand how to do this. please help. thank u :)
Answers
Answered by
bobpursley
Both dice have to be the same to have a perfect square (1,1 or 2,2 or 3,3 or 4,4, or so on)
Think on that.
Figure the probability of getting two numbers the same on each die.
Think on that.
Figure the probability of getting two numbers the same on each die.
Answered by
rebecca
so its 12 to... but what would the unfavourable outcome be?? :S
Answered by
bobpursley
No. If the first die has any number on it, the probability of the second die getting the same number is 1/6.
So the probability of getting a perfect square is 1/6
The unfavorable is 1-1/6
So the probability of getting a perfect square is 1/6
The unfavorable is 1-1/6
Answered by
MathMate
Note:
The favourable combinations are:
1,1 or 2,2 or 3,3 or 4,4 or 5,5 or 6,6 or 1,4 (becaue 1*4 is also a perfect square).
So they add up to 38/216=19/108
The favourable combinations are:
1,1 or 2,2 or 3,3 or 4,4 or 5,5 or 6,6 or 1,4 (becaue 1*4 is also a perfect square).
So they add up to 38/216=19/108
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.