Question

What are the odds in favour for this event?

getting a perfect square when two number cubes labelled 1 to 6 are rolled and the numbers are multiplied.

i don't understand how to do this. please help. thank u :)

Answer 1

Both dice have to be the same to have a perfect square (1,1 or 2,2 or 3,3 or 4,4, or so on)

Think on that.
Figure the probability of getting two numbers the same on each die.

Answer 2

so its 12 to... but what would the unfavourable outcome be?? :S

Answer 3

No. If the first die has any number on it, the probability of the second die getting the same number is 1/6.

So the probability of getting a perfect square is 1/6

The unfavorable is 1-1/6

Answer 4

Note:
The favourable combinations are:
1,1 or 2,2 or 3,3 or 4,4 or 5,5 or 6,6 or 1,4 (becaue 1*4 is also a perfect square).
So they add up to 38/216=19/108