Asked by jane

The energy given off by 300 grams of an alloy as it cools through 50°C raises the temperature of 300 grams of water from 30°C to 40°C. The specific heat of the alloy (in cal/g C ) is:


i know Q=CpM(delta T)

but what is what?
Answered by bobpursley
Heat lost=heat gained
300*c*50=300*4.18*10
Answered by HANA
50
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