3(2i - 7) = 6i - 21

Answer 1

To solve the equation 3(2i - 7) = 6i - 21, we can start by distributing the 3 to the terms inside the parentheses:

3 * 2i - 3 * 7 = 6i - 21

This simplifies to:

6i - 21 = 6i - 21

Since the variables cancel out on both sides of the equation, the equation becomes:

-21 = -21

This is a true statement, which means that the equation is true for all values of i. Therefore, i can be any complex number.