RT= (0.0821)(270) = 22.167
Now, plug in the values into the equation PV=N:
N = (1.8)(2)/(22.167)
N ≈ 0.162 moles
Given that R= 0.0821(L⋅atm) / (mol⋅K) how many moles must be in a 2L container at 1.8 atmospheres with a temperature of 270K?
This is what I have so far, Fill in the blank spots please.
P= 1.8 atm
V= 2L
Answer this: N= ____ ?
R=.0821 L atm/ mol * k
T=270 K
PV=N= (1.8)(2)/ (0.821)(270)
Answer this: RT=______ ?
1 answer
1 answer