A line that contains the point (0, -8) with a slope of 3/2

Answer 1

The equation of the line can be found using the point-slope form of the line equation:

y - y1 = m(x - x1)

Where (x1, y1) is the given point and m is the slope.

Plugging in the values:

y - (-8) = (3/2)(x - 0)

Simplifying:

y + 8 = (3/2)x

The equation of the line is given by:

y = (3/2)x - 8