Find the surface area of a square pyramid with side length 6 yd and slant height 4 yd..
1 answer
The lateral surface area of a square pyramid is given by the formula $A_l=\frac{1}{2}pl$, where $p$ is the perimeter of the base and $l$ is the slant height. The base of the pyramid is a square with side length 6 yd, so the perimeter of the base is $4\cdot6=24$ yd. Thus, the lateral surface area is $\frac12(24\text{ yd})(4\text{ yd})=\boxed{48}$ square yards.