The equation of the line with slope 2/3 and y-intercept 9 can be written in point-slope form as:
y - y1 = m(x - x1)
where m is the slope and (x1, y1) is a point on the line. In this case, the y-intercept (0, 9) can be used as the point.
Plugging in the values, we get:
y - 9 = (2/3)(x - 0)
Simplifying further:
y - 9 = (2/3)x
This equation can also be written in slope-intercept form (y = mx + b):
y = (2/3)x + 9
What is an equation for the line with slope (rate of
change) 2/3 and y-
intercept 9?
1 answer