Question
An oil spill from a tanker in pristine Prince Williams Sound in Alaska begins in a circular shape only 2 ft across. what happens to the area if the diameter is doubling each hour. How large
will the spill be in 24 h?
diameter= 2^(t+1) t is time in hours.
Area= PI*radius^2= PI (diameter/2)^2
= 1/4 PI * 2^(t+1)
check my thinking.
I think i understand the diameter part which it would be:
D= 2(t+1)
2(24+1)
2x25
D=50
I do not understand the Area part though.
Notice the diameter is an exponent. ^means to the power of , as
2^(t+2) is the same as 2<sup>t+1</sup>
Area is related to diameter by the equation I gave.
Area= 1/4 PI * 2<sup>(t+1)</sup>
why don't you just do an example and let me check it?
ok so is the answer (2to the 24 power)squared times pi after 24 hours?
No. Area= 1/4 PI *(2<sup>t+1</sup>)^2
or Area= 1/4 PI (2<sup>24+1</sup>)^2
or Area= 1/4 PI (2<sup>50</sup>)
will the spill be in 24 h?
diameter= 2^(t+1) t is time in hours.
Area= PI*radius^2= PI (diameter/2)^2
= 1/4 PI * 2^(t+1)
check my thinking.
I think i understand the diameter part which it would be:
D= 2(t+1)
2(24+1)
2x25
D=50
I do not understand the Area part though.
Notice the diameter is an exponent. ^means to the power of , as
2^(t+2) is the same as 2<sup>t+1</sup>
Area is related to diameter by the equation I gave.
Area= 1/4 PI * 2<sup>(t+1)</sup>
why don't you just do an example and let me check it?
ok so is the answer (2to the 24 power)squared times pi after 24 hours?
No. Area= 1/4 PI *(2<sup>t+1</sup>)^2
or Area= 1/4 PI (2<sup>24+1</sup>)^2
or Area= 1/4 PI (2<sup>50</sup>)