Question

Apply the Pythagorean Theorem to find the length between (−1, 6) and (5, −2) . Round your answer to the nearest hundredth, if necessary.(1 point)
Responses

14
14

9.22
9.22

10
10

100

Answers

Answer
Apply the Pythagorean Theorem to find the length between the two points. Round your answer to the nearest hundredth, if necessary.

(1 point)
Responses

6:40
6:40

41
41

5.57
5.57

9
Answer
-2 -4
Answered by GPT 3.5
To find the length between the points (-1, 6) and (5, -2), we can use the Pythagorean Theorem.

The formula is: c^2 = a^2 + b^2, where c is the hypotenuse (the distance between the two points) and a and b are the legs (the differences in the x and y coordinates).

Let's calculate the length:

a = (5 - (-1)) = 6
b = (-2 - 6) = -8

Now, we can substitute the values into the formula:

c^2 = 6^2 + (-8)^2
c^2 = 36 + 64
c^2 = 100

Taking the square root of both sides, we find:

c = sqrt(100)
c = 10

Therefore, the length between the points (-1, 6) and (5, -2) is 10.
Answered by GPT 3.5
To find the length between two points using the Pythagorean Theorem, we need to find the differences in the x and y coordinates of the points and then calculate the square root of the sum of their squares.

In this case, you did not provide the specific coordinates of the two points, so I cannot calculate the distance between them. Please provide the coordinates of the two points so that I can assist you further.
Answered by GPT 3.5
To find the length between the points (-2, -4) and the origin (0, 0), we can use the Pythagorean Theorem.

The formula is: c^2 = a^2 + b^2, where c is the hypotenuse (the distance between the two points) and a and b are the differences in the x and y coordinates.

Let's calculate the length:

a = 0 - (-2) = 2
b = 0 - (-4) = 4

Now, we can substitute the values into the formula:

c^2 = 2^2 + 4^2
c^2 = 4 + 16
c^2 = 20

Taking the square root of both sides, we find:

c = sqrt(20)
c ≈ 4.47

Rounding to the nearest hundredth, the length between the points (-2, -4) and the origin is approximately 4.47.

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