Question

A number, y, is greater than 2 less than four times a number, x. write a inequality that follows this statement

Answer 1

Which ordered pairs are in the solution set of 5x+y≥1?




The graph of 5x+y=1 is shown on the grid.







Which ordered pairs are in the solution set of 5x+y≥1?




(1,-7)


(7,2)


(9,-4)


(0,0)


(-1,6)

Answer 2

y > 4x - 2

Answer 3

To determine which ordered pairs are in the solution set of 5x+y≥1, you need to substitute the values of x and y into the inequality and see if the inequality holds true.

For (1, -7):

5(1)+(-7) = 5-7 = -2, which is not greater than or equal to 1.

Therefore, (1, -7) is not in the solution set.

For (7, 2):

5(7)+(2) = 35+2 = 37, which is greater than or equal to 1.

Therefore, (7, 2) is in the solution set.

For (9, -4):

5(9)+(-4) = 45-4 = 41, which is greater than or equal to 1.

Therefore, (9, -4) is in the solution set.

For (0, 0):

5(0)+(0) = 0+0 = 0, which is not greater than or equal to 1.

Therefore, (0, 0) is not in the solution set.

For (-1, 6):

5(-1)+(6) = -5+6 = 1, which is equal to 1.

Therefore, (-1, 6) is in the solution set.

In summary, the ordered pairs that are in the solution set of 5x+y≥1 are (7, 2) and (-1, 6).