A particular hybrid car travels approximately 294 mi on 6 gal of gas. Find the amount of gas required for a 735-mi trip.

Answer 1

To find the amount of gas required for a 735-mi trip, we can set up a proportion with the given information:

294 mi / 6 gal = 735 mi / x gal

Cross-multiplying, we get:

294 mi * x gal = 6 gal * 735 mi

Dividing both sides of the equation by 294 mi, we have:

x gal = (6 gal * 735 mi) / 294 mi

Simplifying, we find:

x gal ≈ 15 gal

Therefore, the amount of gas required for a 735-mi trip is approximately 15 gallons.