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(a^4 - 7a^2b^2 + kb^4) ÷ (a-3b)
I'm not sure how to divide this by long division or otherwise...
2 answers
The method is explained at
http://www.sosmath.com/algebra/factor/fac01/fac01.html
Your particular numerator will only factor easily for certain factors k, such as 6.
The denominator will not be one of the factors, so nothing cancels out. You will get a messy looking answer with a remainder term that is a ratio of a polynomial and x-3
http://www.sosmath.com/algebra/factor/fac01/fac01.html
Your particular numerator will only factor easily for certain factors k, such as 6.
The denominator will not be one of the factors, so nothing cancels out. You will get a messy looking answer with a remainder term that is a ratio of a polynomial and x-3