Asked by Angela---- pLEASE HELP ME
1. A toy manufactor needs a piece of plastic in the shape of a right triangle with the longer leg 1 cm more than the shorter leg. How long should the sides of the triangle be?
a^2+b^2=c^2
x^2+(x+1)^2=(x+2)^2
x^2+x^2+2x+1= x^2+4x+4
2. Martha want to buy a rug for a room that is 11 ft wide and 18 ft. long. She wants to leave a uniform strip of floor around the rug. She can afford to buy 144 sq. feet of carpet. What dimesons should the rug have.
(18-2x)(11-2x)=144
3.A point on the ground 60 ft from the base of the tree, the distance to the top of the tree is 4 ft more than 2 twice the height of the tree.Find the height of the tree.
h^2+60^2=(2h+4)^2
h^2+3600=(2h+4)^2
h^2+3600=(2h+4)(2h+4)
h^2+3600= 4h^2+8h+8h+16
h^2+3600=4h^2+16h+16
-h^2 -h^2
3600=3h^2+16h+16
-3600 -3600
0=3h^2+16h-3584
PLEASE HELP ME OUT IF U KNOW A STORTER WAY TO SOLVE THESE PROBLEMS
a^2+b^2=c^2
x^2+(x+1)^2=(x+2)^2
x^2+x^2+2x+1= x^2+4x+4
2. Martha want to buy a rug for a room that is 11 ft wide and 18 ft. long. She wants to leave a uniform strip of floor around the rug. She can afford to buy 144 sq. feet of carpet. What dimesons should the rug have.
(18-2x)(11-2x)=144
3.A point on the ground 60 ft from the base of the tree, the distance to the top of the tree is 4 ft more than 2 twice the height of the tree.Find the height of the tree.
h^2+60^2=(2h+4)^2
h^2+3600=(2h+4)^2
h^2+3600=(2h+4)(2h+4)
h^2+3600= 4h^2+8h+8h+16
h^2+3600=4h^2+16h+16
-h^2 -h^2
3600=3h^2+16h+16
-3600 -3600
0=3h^2+16h-3584
PLEASE HELP ME OUT IF U KNOW A STORTER WAY TO SOLVE THESE PROBLEMS
Answers
Answered by
bobpursley
1. There are an infinte number of solutions, pick any leg, the other leg is 1cm longer. say 34cm, and 35cm.
2. correct, solve for x
3. h^2+60^2=(2h+4)^2
I would use the quadratic equation, I don't see a factor easily.
2. correct, solve for x
3. h^2+60^2=(2h+4)^2
I would use the quadratic equation, I don't see a factor easily.
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