Question

wo bowling balls of different masses collide while accelerating at 1.875 m/s 2 . The first ball, rolling to the right, weighs 7 kg. The second ball, rolling to the left, weighs 4 kg. What force does the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg?(1 point) Responses 7.5 N to the left 7.5 N to the left 13.125 N to the right 13.125 N to the right 3.73 N to the right 3.73 N to the right 8.875 N to the right

Answer 1

To solve this problem, we need to use Newton's second law of motion, which states that force is equal to mass times acceleration (F = ma).

The mass of the first ball weighing 7 kg is 7 kg and the acceleration is 1.875 m/s^2. Thus, the force exerted by the first ball is F1 = (7 kg)(1.875 m/s^2) = 13.125 N to the right.

Similarly, the mass of the second ball weighing 4 kg is 4 kg and the acceleration is also 1.875 m/s^2. Thus, the force exerted by the second ball is F2 = (4 kg)(1.875 m/s^2) = 7.5 N to the left.

Therefore, the force exerted by the bowling ball weighing 7 kg on the bowling ball weighing 4 kg is 13.125 N to the right.