Asked by songoku
Use synthetic division to determine which of the following are the real zeroes of the function f left parenthesis x right parenthesis equals 3 x cubed plus 10 x squared plus 4 x minus 8.
(1 point)
Responses
negative 3 halves comma 2
Image with alt text: negative 3 halves comma 2
negative 2 comma 2 thirds
Image with alt text: negative 2 comma 2 thirds
negative 2 comma negative 2 thirds comma 2
Image with alt text: negative 2 comma negative 2 thirds comma 2
negative 2 comma 3 halves comma 2
(1 point)
Responses
negative 3 halves comma 2
Image with alt text: negative 3 halves comma 2
negative 2 comma 2 thirds
Image with alt text: negative 2 comma 2 thirds
negative 2 comma negative 2 thirds comma 2
Image with alt text: negative 2 comma negative 2 thirds comma 2
negative 2 comma 3 halves comma 2
Answers
Answered by
lol
is 2 a real zero
Answered by
GPT 3.5
To use synthetic division, we need to find the zeroes of the function. To do this, we will set the function equal to zero and solve for x:
3x^3 + 10x^2 + 4x - 8 = 0
Now, we can use synthetic division with the possible zeroes given to determine which ones are real zeroes.
For the first option, x = -3/2:
-3/2 | 3 10 4 -8
-9 4 -12
-------------
3 1 -8
The resulting polynomial is 3x^2 + x - 8. Since the remainder is not zero, -3/2 is not a real zero.
For the second option, x = -2/3:
-2/3 | 3 10 4 -8
-2 4 -8
-------------
3 8 -4
The resulting polynomial is 3x^2 + 8x - 4. Since the remainder is not zero, -2/3 is not a real zero.
For the third option, x = -2:
-2 | 3 10 4 -8
-6 -8 8
------------
3 4 0
The resulting polynomial is 3x^2 + 4x, which has a remainder of 0. Therefore, -2 is a real zero.
For the fourth option, x = 3/2:
3/2 | 3 10 4 -8
9/2 27/2 33/2
----------------
3 17/2 25/2
The resulting polynomial is 3x^2 + (17/2)x + (25/2), which has a remainder of 0. Therefore, 3/2 is a real zero.
So, the real zeroes of the function f(x) = 3x^3 + 10x^2 + 4x - 8 are -2 and 3/2.
3x^3 + 10x^2 + 4x - 8 = 0
Now, we can use synthetic division with the possible zeroes given to determine which ones are real zeroes.
For the first option, x = -3/2:
-3/2 | 3 10 4 -8
-9 4 -12
-------------
3 1 -8
The resulting polynomial is 3x^2 + x - 8. Since the remainder is not zero, -3/2 is not a real zero.
For the second option, x = -2/3:
-2/3 | 3 10 4 -8
-2 4 -8
-------------
3 8 -4
The resulting polynomial is 3x^2 + 8x - 4. Since the remainder is not zero, -2/3 is not a real zero.
For the third option, x = -2:
-2 | 3 10 4 -8
-6 -8 8
------------
3 4 0
The resulting polynomial is 3x^2 + 4x, which has a remainder of 0. Therefore, -2 is a real zero.
For the fourth option, x = 3/2:
3/2 | 3 10 4 -8
9/2 27/2 33/2
----------------
3 17/2 25/2
The resulting polynomial is 3x^2 + (17/2)x + (25/2), which has a remainder of 0. Therefore, 3/2 is a real zero.
So, the real zeroes of the function f(x) = 3x^3 + 10x^2 + 4x - 8 are -2 and 3/2.
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