Asked by Rachale
That is not what the ? is asking. The ? is asking about how to get the quotient function, not the composite as you solved for. Can you please show us how to get the quotient function solution? Thanks!
I need to find the Quotient Function of the following:
Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:
a. (f/g)(-root3)
b. (g/f)(-1/2)
I need to find the Quotient Function of the following:
Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:
a. (f/g)(-root3)
b. (g/f)(-1/2)
Answers
Answered by
drwls
I have never heard of the term "quotient function". From your description of what it is,I would suggest that you just compute f(x) and g(x) for the x value you are given, and take the ratio.
f(-1/2) = -3 1/4
g(-1/2) = 0
f/g (-1/2) = infinity
The "quotient function" is just f(x)/g(x), which you can write as a ratio of the two functions
f(-1/2) = -3 1/4
g(-1/2) = 0
f/g (-1/2) = infinity
The "quotient function" is just f(x)/g(x), which you can write as a ratio of the two functions
Answered by
Rachale
What about A? Is there a solution for it?
Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:
a. (f/g)(-root3)
Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:
a. (f/g)(-root3)
Answered by
Rachale
Did you combine the two problems? These are two separate functions.
I need to find the Quotient Function of the following:
Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:
a. (f/g)(-root3)
b. (g/f)(-1/2)
I need to find the Quotient Function of the following:
Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:
a. (f/g)(-root3)
b. (g/f)(-1/2)
Answered by
drwls
f/g is (x^2 -3)/(2x+1)
Plug in -sqrt3 for x and compute
g/f is (2x+1)/(x^2 -3)
Plug in -1/2 for x and compute
Plug in -sqrt3 for x and compute
g/f is (2x+1)/(x^2 -3)
Plug in -1/2 for x and compute
Answered by
sophie
inead help on math homework
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.