The quadratic equation can be written as (x - (-11))(x - 5) = 0. This can be expanded as (x + 11)(x - 5) = 0.
When we multiply this out, we get x^2 - 5x + 11x - 55 = 0, which simplifies to x^2 + 6x - 55 = 0.
Therefore, the value of b is 6.
What should be the value of b in x ^ 2 + bx - 55 = 0 so that its solutions are -11 and 5? 6 16 6 16
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