Add: (4d−3)+(12d+4).

To add (4d−3) and (12d+4), we simply combine like terms:

(4d−3) + (12d+4) = 4d + 12d - 3 + 4

Combining the d terms gives us:

4d + 12d = 16d

Combining the constant terms gives us:

-3 + 4 = 1

So, the final expression is:

16d + 1.

Add: (2m−3)+(3n−1)+(3m+1).

The answers are:
1. 1 1/2x + 1 1/2
2. 16d + 1
3. 5m + 3n - 3
4. 19b + 10
5. -3g - 12
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