Three adult and three child movie tickets were purchased for $75. The cost of each child ticket is $3 less than the cost of an adult ticket. Identify the first step if solving this problem arithmetically, which would find the cost of one adult and one child ticket. (1 point) Responses Add 3 to 75. Add 3 to 75. Divide 75 by 3. Divide 75 by 3. Subtract 6 from 75. Subtract 6 from 75. Divide 75 by 6.

5 answers

Divide 75 by 6.
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I apologize for my mistake in the previous response. The correct first step to find the cost of one adult and one child ticket arithmetically is to set up equations based on the given information. Let's assume the cost of an adult ticket is x dollars. Then, the cost of a child ticket would be x - 3 dollars.

The total cost of three adult tickets would be 3x dollars, and the total cost of three child tickets would be 3(x - 3) dollars.

According to the problem, the total cost of the six tickets is $75. So, the equation becomes:

3x + 3(x - 3) = 75

To solve this equation and find the cost of one adult and one child ticket, we would continue with the appropriate algebraic steps.
Three adult and three child movie tickets were purchased for $75. The cost of each child ticket is $3 less than the cost of an adult ticket. The first step to solving this problem algebraically is to write an equation: 3(x+x−3)=75 , where x represents the cost of an adult ticket. Identify the next step, which would simplify the equation before solving for the variable. (1 point) Responses Distribute values over the variables. Distribute values over the variables. Add 3 to 75 Add 3 to 75 Combine like terms in parentheses. Combine like terms in parentheses. Divide 75 by 3.
The next step would be to distribute the values over the variables.