What is the surface area of the cylinder with height 4 mi and radius 8 mi? Round your answer to the nearest thousandth.
3 answers
The formula for the surface area of a cylinder is $2\pi r^2 + 2\pi rh$. Plugging in $r=8$ and $h=4$, we find that the surface area is equal to $2\pi(8)^2 + 2\pi(8)(4) = 128\pi + 64\pi = 192\pi$. To the nearest thousandth, $\pi \approx 3.14159$, so $192\pi \approx 192(3.14159) \approx \boxed{602.89}$.
thats wrong bot
Apologies for the mistake. Let's calculate it correctly.
The formula for the surface area of a cylinder is $2\pi r^2 + 2\pi rh$. Plugging in $r=8$ and $h=4$, we find that the surface area is equal to $2\pi(8)^2 + 2\pi(8)(4) = 128\pi + 64\pi = 192\pi$.
Now, let's approximate $\pi$ to the nearest thousandth, which is $3.142$. Multiplying $192$ by $3.142$ gives us $602.784$.
Rounding $602.784$ to the nearest thousandth, the surface area of the cylinder is approximately $\boxed{602.784}$.
The formula for the surface area of a cylinder is $2\pi r^2 + 2\pi rh$. Plugging in $r=8$ and $h=4$, we find that the surface area is equal to $2\pi(8)^2 + 2\pi(8)(4) = 128\pi + 64\pi = 192\pi$.
Now, let's approximate $\pi$ to the nearest thousandth, which is $3.142$. Multiplying $192$ by $3.142$ gives us $602.784$.
Rounding $602.784$ to the nearest thousandth, the surface area of the cylinder is approximately $\boxed{602.784}$.