The surface area of a cylinder is given by the formula $2\pi r^2 + 2\pi rh$, where $r$ is the radius of the base and $h$ is the height.
Substituting the given values, we have:
$2\pi(5\text{ km})^2 + 2\pi(5\text{ km})(4\text{ km})$
$= 2\pi(25\text{ km}^2) + 2\pi(20\text{ km}^2)$
$= 50\pi + 40\pi$
$= 90\pi$
Rounded to the nearest thousandth, this is approximately $\boxed{282.743\text{ km}^2}$.
What is the surface area of the cylinder with height 4 km and radius 5 km? Round your answer to the nearest thousandth.
1 answer