What is square root of 12 simplified?
13 answers
The square root of 12 simplified is 2√3.
What is square root of 18 simplified?
The square root of 18 simplified is 3√2.
What is square root of 125 simplified
The square root of 125 simplified is 5√5.
What is 3 to the cubic root of 54
3 to the cubic root of 54 is approximately 9.676.
Rewrite the irrational square root 48 as the product of an integer and another irrational square root.
To rewrite the irrational square root of 48 as the product of an integer and another irrational square root, we can look for the largest perfect square that divides evenly into 48. The largest perfect square that divides evenly into 48 is 16.
We can rewrite 48 as 16 * 3. Therefore, we can write the square root of 48 as the square root of 16 times the square root of 3.
The square root of 16 is 4, so we can rewrite the square root of 48 as 4 * square root of 3.
Therefore, the square root of 48 can be written as the product of an integer (4) and an irrational square root (square root of 3).
We can rewrite 48 as 16 * 3. Therefore, we can write the square root of 48 as the square root of 16 times the square root of 3.
The square root of 16 is 4, so we can rewrite the square root of 48 as 4 * square root of 3.
Therefore, the square root of 48 can be written as the product of an integer (4) and an irrational square root (square root of 3).
What is the irrational square root 28 simplified?
The square root of 28 simplified is 2√7.
Rewrite the irrational cube root 3 square root of 48 as the product of an integer and another irrational cube root
To rewrite the irrational cube root of (3 * √48), we need to determine perfect cube factors of 48. The largest perfect cube factor of 48 is 8 (2^3).
We can rewrite 48 as 8 * 6. Now we can simplify the expression as follows:
∛(3 * √48) = ∛(3 * √(8 * 6)) = ∛(3 * √8 * √6)
Since the cube root of 8 is 2 and the square root of 6 cannot be further simplified, we end up with:
2 * ∛(3 * 2√6)
Hence, the irrational cube root (∛) of (3 * √48) can be rewritten as the product of an integer (2) and another irrational cube root (∛) of (3 * 2√6).
We can rewrite 48 as 8 * 6. Now we can simplify the expression as follows:
∛(3 * √48) = ∛(3 * √(8 * 6)) = ∛(3 * √8 * √6)
Since the cube root of 8 is 2 and the square root of 6 cannot be further simplified, we end up with:
2 * ∛(3 * 2√6)
Hence, the irrational cube root (∛) of (3 * √48) can be rewritten as the product of an integer (2) and another irrational cube root (∛) of (3 * 2√6).
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