Asked by Beth
State the center and the radius of the circle represented by the equation
(x + 1)^2 + (y – 5)^2 = 64
(x + 1)^2 + (y – 5)^2 = 64
Answers
Answered by
Reiny
in the general equation of a circle
(x-h)^2 + (y-k)^2 = r^2
the centre is (h,k) and the radius is r
can you match this with your given equation?
(x-h)^2 + (y-k)^2 = r^2
the centre is (h,k) and the radius is r
can you match this with your given equation?
Answered by
Beth
ok based on that I would say the radius is 8 cause 8*8 = 64 and the center is (1,5)? Or do the signs change because of the equation
(x-h)^2 + (y-k)^2 = r^2 making the center (-1,5)?
(x-h)^2 + (y-k)^2 = r^2 making the center (-1,5)?
Answered by
Reiny
radius is correct,
the centre is (-1,5)
the centre is (-1,5)
Answered by
Beth
That is what I thought, so the standard form would be
(x-(-1]^2 + (y-5)^2 = 64
(x-(-1]^2 + (y-5)^2 = 64
Answered by
Reiny
yes,
I just mentally change the sign I see in the bracket
I just mentally change the sign I see in the bracket
Answered by
Beth
Great! Thanks for the help! So R= 8 and the center is (-1,5) got it! Thanks again!
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