Asked by Alicia
Given that f(x) = x^2-3 and g(x) = 2x+1, find each of the following, if it exists.
a. (fg)(-root3)
b. (gf)(-1/2)
a. (fg)(-root3)
b. (gf)(-1/2)
Answers
Answered by
Reiny
do you mean f(g(x)) ?
f(g(x))
= (g(x))^2 - 3
= (2x+1)^2 - 3
then (f(g(-√3))
= (-2√3 + 1)^2 - 3
= 12 - 4√3 + 1 - 3
= 10 - 4√3
do the other one the same way
remember this time you want
g(f(x))
= g(x^2-3)
= 2(x^2-3) + 1
f(g(x))
= (g(x))^2 - 3
= (2x+1)^2 - 3
then (f(g(-√3))
= (-2√3 + 1)^2 - 3
= 12 - 4√3 + 1 - 3
= 10 - 4√3
do the other one the same way
remember this time you want
g(f(x))
= g(x^2-3)
= 2(x^2-3) + 1
Answered by
Alicia
The first one was (fg)(-root3). Does this answer your ? Thanks for the help!
Answered by
Alicia
What happend to the (-1/2) in the second problem?
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