Question

(4d−3)+(12d+4)

Answer 1

12(x+4)+14(4x−2)

Answer 2

sorry i put that in there wrong its
1/2(x+4)+1/4(4x−2)

Answer 3

don't simplifie the question

Answer 4

(2m−3)+(3n−1)+(3m+1)

Answer 5

2(10b+4)−(b−2)

Answer 6

(3g−4)−2(3g+4)

Answer 7

9(k+13)+10(12k−1) .(1 point)
Responses

14k+13
14 k plus 13

1912k−23
19 Start Fraction 1 over 2 End Fraction k minus Start Fraction 2 over 3 End Fraction

14k−23
14 k minus Start Fraction 2 over 3 End Fraction

14k−7

Answer 8

choose on of my answers please

Answer 9

4(g−2)+(g+2) .(1 point)
Responses

5g−6
5 g minus 6

5g+10
5 g plus 10

5g
5 g

5g−10

Answer 10

(h+k)−(2k−h) .(1 point)
Responses

2h−k
2 h minus k

2h+k
2 h plus k

−k
negative k

−2h−k

Answer 11

(p−3)−(2.4+2p) .(1 point)
Responses

p−5.4
p minus 5.4

−p−5.4
negative p minus 5.4

3p−5.4
3 p minus 5.4

−p+5.4

Answer 12

To solve the expression (4d−3)+(12d+4), we need to combine like terms.

First, we distribute the positive sign to each term inside the parentheses:

4d - 3 + 12d + 4

Next, we can combine the terms with the variable (4d and 12d) and the constant terms (-3 and 4):

(4d + 12d) + (-3 + 4)

This simplifies to:

16d + 1

Therefore, (4d−3)+(12d+4) simplifies to 16d + 1.

Answer 13

To solve the expression 12(x+4)+14(4x−2), we need to distribute the coefficients to each term inside the parentheses and then combine like terms.

First, we distribute 12 to each term inside the parentheses:

12(x) + 12(4) + 14(4x) - 14(2)

This simplifies to:

12x + 48 + 56x - 28

Next, we can combine the terms with the variable (12x and 56x) and the constant terms (48 and -28):

12x + 56x + 48 - 28

This simplifies to:

68x + 20

Therefore, 12(x+4)+14(4x−2) simplifies to 68x + 20.

Answer 14

No problem! To solve the expression 1/2(x+4)+1/4(4x−2), we need to distribute the coefficients and then combine like terms.

First, we distribute 1/2 to each term inside the first set of parentheses:

1/2 * x + 1/2 * 4

This simplifies to:

1/2x + 2

Next, we distribute 1/4 to each term inside the second set of parentheses:

1/4 * 4x + 1/4 * (-2)

This simplifies to:

1x + (-1/2)

Now we can combine the terms:

1/2x + 2 + 1x - 1/2

We can combine the terms with the variable (1/2x and 1x) and the constant terms (2 and -1/2):

(1/2x + 1x) + (2 - 1/2)

This simplifies to:

(3/2x) + (3/2)

Therefore, 1/2(x+4)+1/4(4x−2) simplifies to (3/2x) + (3/2).

Answer 15

I apologize for simplifying the expression. To solve the expression 1/2(x+4)+1/4(4x−2) without simplifying, we can distribute the coefficients and rewrite the expression as follows:

1/2(x) + 1/2(4) + 1/4(4x) - 1/4(2)

This simplifies to:

1/2x + 2/2 + 1/4 * 4x - 1/4 * 2

Further simplifying, we have:

1/2x + 1 + 1x/4 - 1/2

Next, we can combine the terms with the variable (1/2x and 1x/4):

1/2x + 1x/4 + 1 - 1/2

To combine the fractions with different denominators, we need to find a common denominator:

The common denominator for 2, 4, and 2 is 4.

Thus, we can rewrite the expression as:

2/4x + 1/4x + 4/4 - 2/4

Combining the fractions, we have:

(2x + 1)/4x + 2/4

Since the numerators have a common factor of 1, we can simplify further:

(2x + 1)/4x + 1/2

Therefore, the expression 1/2(x+4)+1/4(4x−2) can be written as (2x + 1)/4x + 1/2 without simplification.

Answer 16

To solve the expression (2m−3)+(3n−1)+(3m+1), we need to combine like terms.

First, we can add the terms with the variable m (2m and 3m):

2m + 3m = 5m

Next, we add the terms with the variable n (3n):

5m + 3n

Then, we add the constant terms (-3, -1, and 1):

-3 - 1 + 1 = -3

Finally, we combine the terms with the variables (5m and 3n) and the constant term (-3):

5m + 3n - 3

Therefore, (2m−3)+(3n−1)+(3m+1) simplifies to 5m + 3n - 3.

Answer 17

To solve the expression 2(10b+4)−(b−2), we need to distribute the coefficients and then combine like terms.

First, we distribute the coefficient 2 to each term inside the parentheses:

2 * 10b + 2 * 4 - (b - 2)

This simplifies to:

20b + 8 - (b - 2)

Next, we distribute the negative sign (-1) to each term inside the other parentheses:

20b + 8 - b + 2

This simplifies further to:

19b + 10

Therefore, 2(10b+4)−(b−2) simplifies to 19b + 10.

Answer 18

To solve the expression (3g−4)−2(3g+4), we need to distribute the coefficient -2 to each term inside the parentheses and then combine like terms.

First, we distribute the coefficient -2 to each term inside the second set of parentheses:

(3g - 4) - 2*3g - 2*4

This simplifies to:

3g - 4 - 6g - 8

Next, we can combine the terms with the variable (-6g and 3g):

(3g - 6g) - 4 - 8

This simplifies further to:

-3g - 12

Therefore, (3g−4)−2(3g+4) simplifies to -3g - 12.

Answer 19

To solve the expression 9(k+13)+10(12k−1), we need to distribute the coefficients and then combine like terms.

First, we distribute 9 to each term inside the first set of parentheses:

9k + 9(13)

This simplifies to:

9k + 117

Next, we distribute 10 to each term inside the second set of parentheses:

10(12k) + 10(-1)

This simplifies to:

120k - 10

Now we can combine the terms:

9k + 117 + 120k - 10

We can combine the terms with the variable (9k and 120k) and the constant terms (117 and -10):

(9k + 120k) + (117 - 10)

This simplifies to:

129k + 107

Therefore, 9(k+13)+10(12k−1) simplifies to 129k + 107.

Answer 20

Out of the provided answer choices, the correct answer is:

14k−7

Answer 21

To solve the expression 4(g−2)+(g+2), we need to distribute the coefficients and then combine like terms.

First, we distribute 4 to each term inside the first set of parentheses:

4g - 4(2)

This simplifies to:

4g - 8

Next, we distribute 1 to each term inside the second set of parentheses:

g + 2

Now we can combine the terms:

4g - 8 + g + 2

We can combine the terms with the variable (4g and g) and the constant terms (-8 and 2):

4g + g - 8 + 2

This simplifies to:

5g - 6

Therefore, 4(g−2)+(g+2) simplifies to 5g - 6.

Answer 22

To solve the expression (h+k)−(2k−h), we need to distribute the negative sign to each term inside the second set of parentheses and then combine like terms.

First, we distribute the negative sign to each term inside the second set of parentheses:

(h + k) - 2k + h

Now we can combine the terms:

h + k - 2k + h

We can combine the terms with the variable (h and h) and the constant terms (k and -2k):

2h + k - 2k

Now we combine the like terms:

2h - k

Therefore, (h+k)−(2k−h) simplifies to 2h - k.

Answer 23

To solve the expression (p−3)−(2.4+2p), we need to distribute the negative sign to each term inside the second set of parentheses and then combine like terms.

First, we distribute the negative sign to each term inside the second set of parentheses:

(p - 3) - 2.4 - 2p

Now we can combine the terms:

p - 3 - 2.4 - 2p

Next, we combine the terms with the variable (p and -2p) and the constant terms (-3 and -2.4):

(p - 2p) - 3 - 2.4

This simplifies to:

-p - 3 - 2.4

Combining the constant terms, we have:

-p - 5.4

Therefore, (p−3)−(2.4+2p) simplifies to -p - 5.4.