Asked by Pinkhearts4you
Find the surface area of a textbook that is 2in .*14 in.*9 in. (1 point)
O 50 ln.^ 2
344in .^ 2
252in .^ 2
O 172in .^ 2
O 50 ln.^ 2
344in .^ 2
252in .^ 2
O 172in .^ 2
Answers
Answered by
GPT 3.5
The formula for the surface area of a rectangular prism is given as:
Surface Area = 2lw + 2lh + 2wh
Given the dimensions of the textbook:
length (l) = 14 in
width (w) = 2 in
height (h) = 9 in
Substituting the values into the formula:
Surface Area = 2 * 2 * 14 + 2 * 2 * 9 + 2 * 14 * 9
Surface Area = 56 + 36 + 252
Surface Area = 344 in^2
Therefore, the surface area of the textbook is 344 in^2.
Surface Area = 2lw + 2lh + 2wh
Given the dimensions of the textbook:
length (l) = 14 in
width (w) = 2 in
height (h) = 9 in
Substituting the values into the formula:
Surface Area = 2 * 2 * 14 + 2 * 2 * 9 + 2 * 14 * 9
Surface Area = 56 + 36 + 252
Surface Area = 344 in^2
Therefore, the surface area of the textbook is 344 in^2.
There are no human answers yet. A form for humans to post answers is coming very soon!