graph: 9,7 8,6 7,8 7,7 5,7 5,8 4,8 3.5,8.5 2,9 1,9.5

Question

Write an equation in slope-intercept form of the trend line. (1 point) Responses y=−58x+9 y equals negative Start Fraction 5 over 8 End Fraction x plus 9 y=−14x+9 y equals negative Start Fraction 1 over 4 End Fraction x plus 9 y=−14x y equals negative Start Fraction 1 over 4 End Fraction x y=1x+9

Answer 1

To find the equation of the trend line, we need to find the slope and y-intercept. We will use the formula for slope:

m = (y2 - y1)/(x2 - x1)

Let's choose two points from the given data: (9,7) and (1,9.5)

m = (7 - 9.5)/(9 - 1)
m = -2.5/8
m = -5/16

Now, let's use the slope-intercept form of a line:

y = mx + b

We can substitute the slope we found (-5/16) for m:

y = (-5/16)x + b

Now, let's choose one of the points from the given data to find the value of b. Let's use the point (9,7).

7 = (-5/16)(9) + b
7 = (-45/16) + b

To find b, we need to solve for it:

b = 7 + 45/16
b = (112 + 45)/16
b = 157/16

So the equation of the trend line in slope-intercept form is:

y = (-5/16)x + 157/16

Answer 2

choose the options for the problem

Answer 3

Apologies for the confusion. Let's go through the options given:

y = −58x + 9

y equals negative 5/8 x plus 9

y = −14x + 9

y equals negative 1/4 x plus 9

None of these equations match the one we derived, which is:

y = (-5/16)x + 157/16

Therefore, the correct equation in slope-intercept form of the trend line is not listed among these options.