Asked by Chemically Confused
Can someone give me some directions as to how to reach the answer for this problem:
A 0.608g sample of fertilizer contained nitrogen as ammonium sulfate,
(NH4)2 SO4(s)+2NaOH(aq)-->Na2SO4(aq)+ 2H2O(l)+2NH3(g)
The ammonia was collected in 46.3 mL of 0.213 M HCL (hydrochloric acid), with which it reacted.
NH3(g)+HCL(aq)-->NH4Cl(aq)
This solution was titrated for excess hydrochloric acid with 44.3 mL of 0.128 M NaOH
NaOH(aq)+HCL(aq)NaCL(aq)+H2O(l)
What is the percentage of nitrogen in the fertilizer?
The answer is 9.66%
A 0.608g sample of fertilizer contained nitrogen as ammonium sulfate,
(NH4)2 SO4(s)+2NaOH(aq)-->Na2SO4(aq)+ 2H2O(l)+2NH3(g)
The ammonia was collected in 46.3 mL of 0.213 M HCL (hydrochloric acid), with which it reacted.
NH3(g)+HCL(aq)-->NH4Cl(aq)
This solution was titrated for excess hydrochloric acid with 44.3 mL of 0.128 M NaOH
NaOH(aq)+HCL(aq)NaCL(aq)+H2O(l)
What is the percentage of nitrogen in the fertilizer?
The answer is 9.66%
Answers
Answered by
Tey
I get 9.86 something...
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.