Write the equation of the line in slope-intercept form.

Question

(0,2) (1,-1)

Answer 1

To find the equation of the line in slope-intercept form, we first need to find the slope of the line.
The slope, denoted by m, can be calculated using the formula:

m = (y2 - y1) / (x2 - x1)

Using the coordinates (0,2) and (1,-1), we can substitute the values into the formula:

m = (-1 - 2) / (1 - 0)
m = -3 / 1
m = -3

Next, we can use the slope-intercept form of the equation of a line, y = mx + b, where m is the slope and b is the y-intercept, and substitute the slope and the coordinates of one of the points (in this case, we'll use (0,2)) into the equation:

2 = (-3)(0) + b
2 = 0 + b
b = 2

Therefore, the equation of the line in slope-intercept form is:

y = -3x + 2

Answer 2

(3,0) (0,-2)

Answer 3

To find the equation of the line in slope-intercept form, we first need to find the slope of the line.
The slope, denoted by m, can be calculated using the formula:

m = (y2 - y1) / (x2 - x1)

Using the coordinates (3,0) and (0,-2), we can substitute the values into the formula:

m = (-2 - 0) / (0 - 3)
m = -2 / -3
m = 2/3

Next, we can use the slope-intercept form of the equation of a line, y = mx + b, where m is the slope and b is the y-intercept, and substitute the slope and the coordinates of one of the points (in this case, we'll use (3,0)) into the equation:

0 = (2/3)(3) + b
0 = 2 + b
b = -2

Therefore, the equation of the line in slope-intercept form is:

y = (2/3)x - 2

Answer 4

Given the equation y=−2x+2 , what is the slope? Write your answer as an integer

Answer 5

The slope of the equation y = -2x + 2 is -2.

Answer 6

Given the equation y=34x−2 what is the y -intercept? Write your answer as an ordered pair

Answer 7

The y-intercept of the equation y = 34x - 2 is (0, -2).

Answer 8

(1,-1) (0,-4)

Answer 9

To find the equation of the line in slope-intercept form, we first need to find the slope of the line.
The slope, denoted by m, can be calculated using the formula:

m = (y2 - y1) / (x2 - x1)

Using the coordinates (1,-1) and (0,-4), we can substitute the values into the formula:

m = (-4 - (-1)) / (0 - 1)
m = (-4 + 1) / (-1)
m = -3 / (-1)
m = 3

Next, we can use the slope-intercept form of the equation of a line, y = mx + b, where m is the slope and b is the y-intercept, and substitute the slope and the coordinates of one of the points (in this case, we'll use (1,-1)) into the equation:

-1 = 3(1) + b
-1 = 3 + b
b = -4

Therefore, the equation of the line in slope-intercept form is:

y = 3x - 4

Answer 10

(0,1) (1,-4)

Answer 11

To find the equation of the line in slope-intercept form, we first need to find the slope of the line.
The slope, denoted by m, can be calculated using the formula:

m = (y2 - y1) / (x2 - x1)

Using the coordinates (0,1) and (1,-4), we can substitute the values into the formula:

m = (-4 - 1) / (1 - 0)
m = -5 / 1
m = -5

Next, we can use the slope-intercept form of the equation of a line, y = mx + b, where m is the slope and b is the y-intercept, and substitute the slope and the coordinates of one of the points (in this case, we'll use (0,1)) into the equation:

1 = (-5)(0) + b
1 = 0 + b
b = 1

Therefore, the equation of the line in slope-intercept form is:

y = -5x + 1

Answer 12

Graph the linear equation y=−3x+2 .

Answer 13

The graph of the linear equation y = -3x + 2 is a straight line. To graph it, we can plot a few points and then draw a line through them.

Here are a few points we can use:

When x = 0, y = -3(0) + 2 = 2, so we have the point (0, 2).
When x = 1, y = -3(1) + 2 = -3 + 2 = -1, so we have the point (1, -1).
When x = -1, y = -3(-1) + 2 = 3 + 2 = 5, so we have the point (-1, 5).

Plotting those points, we can then draw a line passing through them:

|
5 |
| *
2 | *
|_____________
-1 0 1 2

The line passes through the points (0, 2), (1, -1), and (-1, 5), and extends infinitely in both directions.

Answer 14

graph of y=−13x+4 ?

Answer 15

To graph the linear equation y = -13x + 4, we can plot a few points and then draw a line through them.

Here are a few points we can use:

When x = 0, y = -13(0) + 4 = 4. So we have the point (0, 4).
When x = 1, y = -13(1) + 4 = -13 + 4 = -9. So we have the point (1, -9).
When x = -1, y = -13(-1) + 4 = 13 + 4 = 17. So we have the point (-1, 17).

Plotting those points, we can then draw a line passing through them:

|
17 |
| *
4 | *
|______________
-1 0 1 2

The line passes through the points (0, 4), (1, -9), and (-1, 17), and extends infinitely in both directions.

Answer 16

y=23x−1

Answer 17

To graph the linear equation y = 23x - 1, we can plot a few points and then draw a line through them.

Here are a few points we can use:

When x = 0, y = 23(0) - 1 = -1. So we have the point (0, -1).
When x = 1, y = 23(1) - 1 = 23 - 1 = 22. So we have the point (1, 22).
When x = -1, y = 23(-1) - 1 = -23 - 1 = -24. So we have the point (-1, -24).

Plotting those points, we can then draw a line passing through them:

|
22 |
| *
-1 | *
|______________
-1 0 1 2

The line passes through the points (0, -1), (1, 22), and (-1, -24), and extends infinitely in both directions.

Answer 18

solve y=2/3x-1

Answer 19

To solve the equation y = (2/3)x - 1, we can equate y to a specific value and then solve for x.

Let's say we want to solve for when y = 0:

0 = (2/3)x - 1

Add 1 to both sides:

1 = (2/3)x

To isolate x, multiply both sides by 3/2:

(3/2) * 1 = (3/2) * (2/3)x

3/2 = x

So, x = 3/2.

Therefore, when y is 0, x is 3/2.

The solution to the equation is (3/2, 0).