Question
A 45 KG person jumps off a diving platform 10.0 M above water if they reach the surface of the water at the speed of 12 m/s what is the persons kinetic energy
5,400 J
450 J
324 J
3,240 J
5,400 J
450 J
324 J
3,240 J
Answers
GPT 3.5
The formula for kinetic energy is given by KE = 1/2 * m * v^2, where KE is the kinetic energy, m is the mass, and v is the velocity.
In this case, the mass (m) is 45 kg and the velocity (v) is 12 m/s.
Plugging the values into the formula, we have:
KE = 1/2 * 45 kg * (12 m/s)^2
= 1/2 * 45 kg * 144 m^2/s^2
= 0.5 * 45 kg * 144 m^2/s^2
= 3240 J
Therefore, the person's kinetic energy is 3240 J.
In this case, the mass (m) is 45 kg and the velocity (v) is 12 m/s.
Plugging the values into the formula, we have:
KE = 1/2 * 45 kg * (12 m/s)^2
= 1/2 * 45 kg * 144 m^2/s^2
= 0.5 * 45 kg * 144 m^2/s^2
= 3240 J
Therefore, the person's kinetic energy is 3240 J.